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9(16)=x^2
We move all terms to the left:
9(16)-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+916=0
a = -1; b = 0; c = +916;
Δ = b2-4ac
Δ = 02-4·(-1)·916
Δ = 3664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3664}=\sqrt{16*229}=\sqrt{16}*\sqrt{229}=4\sqrt{229}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{229}}{2*-1}=\frac{0-4\sqrt{229}}{-2} =-\frac{4\sqrt{229}}{-2} =-\frac{2\sqrt{229}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{229}}{2*-1}=\frac{0+4\sqrt{229}}{-2} =\frac{4\sqrt{229}}{-2} =\frac{2\sqrt{229}}{-1} $
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